If were to take the average number of marketers at five of the companies, excluding Fermion, then this average would be approximately how many employees larger than if Fermion were included in the average?

Question

Satt Academy · Accepted Answer

প্রশ্নে বলা হচ্ছে যে, Fermion ছাড়া দুটি কোম্পানির গড় Marketer দের সংখ্যা নিতে হলে ঐ সংখ্যা Fermion সহ গড়ের সংখ্যার চেয়ে কত বেশি হবে?

Fermion ছাড়া বাকি ১টি কোম্পানির Marketer দের গড় হলো = $\frac{58 + 35 + 67 + 46 + 52}{5}$ =51.6

এখানে Fermion 4 Marketer দের সংখ্যা = 18

$∴$ Fermion সহ Marketer দের সংখ্যা গড় = $\frac{258 + 18}{6} = \frac{276}{6} = 46$

$∴$ অতএব, গড় কমবে = 51.6 - 46 = 5.6 (answer)

If were to take the average number of marketers at five of the companies, excluding Fermion, then this average would be approximately how many employees larger than if Fermion were included in the average?

Question:
If were to take the average number of marketers at five of the companies, excluding Fermion, then this average would be approximately how many employees larger than if Fermion were included in the average?

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Promotion

If were to take the average number of marketers at five of the companies, excluding Fermion, then this average would be approximately how many employees larger than if Fermion were included in the average?

Question: If were to take the average number of marketers at five of the companies, excluding Fermion, then this average would be approximately how many employees larger than if Fermion were included in the average?

English

Related Question

Promotion

Question:
If were to take the average number of marketers at five of the companies, excluding Fermion, then this average would be approximately how many employees larger than if Fermion were included in the average?